問題
$\dfrac{5}{16}\div0.625-5\times\bigg(0.4-\dfrac{1}{3}\bigg)=◻︎$
解説
$\dfrac{5}{16}\div0.625-5\times\bigg(0.4-\dfrac{1}{3}\bigg)\\$
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$=\dfrac{5}{16}\div\dfrac{5}{8}-5\times\dfrac{1}{15}\\$
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$=\dfrac{1}{2}-\dfrac{1}{3}\\$
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$=\dfrac{1}{6}$より, $◻︎=\dfrac{1}{6}$になります.