問題
次の式を因数分解せよ.
解説
- (1) $x^2-6x+9-y^2$
- $=(x-3)^2-y^2$
$=$$(x+y-3)(x-y-3)$
- $=(x-3)^2-y^2$
- (2) $x^2-y^2+4y-4$
- $=x^2-(y-2)^2$
$=$$(x+y-2)(x-y+2)$
- $=x^2-(y-2)^2$
- (3) $4x^2-4y^2+4y-1$
- $=4x^2-(2y-1)^2$
$=$$(2x+2y-1)(2x-2y+1)$
- $=4x^2-(2y-1)^2$
- (4) $x^2-2xy+y^2-9z^2$
- $=(x-y)^2-9z^2$
$=$$(x-y+3z)(x-y-3z)$
- $=(x-y)^2-9z^2$
