問題
次の式を展開せよ.
解説
- (1)$(3x – 5y)(5y + 3x)$
- $=(3x-5y)(3x+5y)$
$=$$9x^2-25y^2$
- $=(3x-5y)(3x+5y)$
- (2) $(-2x + 3y)^2$
- $=$$4x^2-12xy+9y^2$
- (3) $(x + 3)(x + 4)$
- $=$$x^2+7x+12$
- (4) $(x – 4y)(x – 2y)$
- $=$$x^2-6xy+8y^2$
- (5) $(2x + 3a)(x – 4a)$
- $=2x^2+(-8+3)ax-12a^2$
- $=$$2x^2-5ax-12a^2$