問題
$2\times\bigg(\dfrac{1}{2}-\dfrac{1}{3}\bigg)+3\times\bigg(\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}\bigg)+4\times\bigg(\dfrac{2}{3}+\dfrac{1}{4}\bigg)+5\times\dfrac{1}{4}=◻︎$
解説
$2\times\dfrac{1}{6}+3\times\dfrac{7}{12}+4\times\dfrac{11}{12}+5\times\dfrac{1}{4}$
$=\dfrac{1}{3}+\dfrac{7}{4}+\dfrac{11}{3}+\dfrac{5}{4}$
$=3+4=7$より, $◻︎=7$となります.
