問題
次の計算をしなさい。但し, 解答は答えのみでよい。
解説
- $(1)$ $4\dfrac{1}{2}\times\dfrac{1}{3}\div0.75-\dfrac{3}{8}\times2$
- $\dfrac{9}{2}\times\dfrac{1}{3}\times\dfrac{4}{3}-\dfrac{3}{8}\times2$
$=2-\dfrac{3}{4}$
$=$$1\dfrac{1}{4}$
- $\dfrac{9}{2}\times\dfrac{1}{3}\times\dfrac{4}{3}-\dfrac{3}{8}\times2$
- $(2)$ $201\times8.9+201\times1.1+12$
- $201\times(8.9+1.1)+12$
$=201\times10+12$
$=$$2022$
- $201\times(8.9+1.1)+12$
- $(3)$ $\bigg(\dfrac{5}{4}+\dfrac{11}{3}+\dfrac{13}{5}\bigg)-5$
- $(1+3+2-5)+\bigg(\dfrac{1}{4}+\dfrac{2}{3}+\dfrac{3}{5}\bigg)$
$=1+\dfrac{15+40+36}{60}$
$=1+\dfrac{91}{60}$
$=$$2\dfrac{31}{60}$
- $(1+3+2-5)+\bigg(\dfrac{1}{4}+\dfrac{2}{3}+\dfrac{3}{5}\bigg)$
- $(4)$ $\dfrac{1}{1\times3}+\dfrac{1}{2\times4}+\dfrac{1}{3\times5}+\dfrac{1}{4\times6}$
- $\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{8}+\dfrac{1}{24}$
$\dfrac{2}{5}+\dfrac{1}{6}$
$=\dfrac{12+5}{30}=$$\dfrac{17}{30}$
- $\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{8}+\dfrac{1}{24}$