問題
次の計算をしなさい. また, 解答は答えのみでよい.
解説
- (1) $2\dfrac{2}{3}\times0.75-\dfrac{5}{4}\div\dfrac{3}{2}\times\dfrac{8}{9}$
- $\dfrac{8}{3}\times\dfrac{3}{4}-\dfrac{5}{4}\times\dfrac{2}{3}\times\dfrac{8}{9}$
$=2-\dfrac{20}{27}$
$=$$1\dfrac{7}{27}$
- $\dfrac{8}{3}\times\dfrac{3}{4}-\dfrac{5}{4}\times\dfrac{2}{3}\times\dfrac{8}{9}$
- (2) $2021\times2021-2018\times2024$
- $2021\times2021-(2021-3)\times(2021+3)$
$=2021\times2021-(2021\times2021-3\times3)$
$=$$9$
- $2021\times2021-(2021-3)\times(2021+3)$
- (3) $\dfrac{3}{2}+\dfrac{8}{3}+\dfrac{15}{4}+\dfrac{24}{5}$
- $1+\dfrac{1}{2}+2+\dfrac{2}{3}+3+\dfrac{3}{4}+4+\dfrac{4}{5}$
$=10+\dfrac{30+40+45+48}{60}$
$=$$12\dfrac{43}{60}$
- $1+\dfrac{1}{2}+2+\dfrac{2}{3}+3+\dfrac{3}{4}+4+\dfrac{4}{5}$
- (4) $\dfrac{1}{1\times2\times3}+\dfrac{1}{2\times3\times4}+\dfrac{1}{3\times4\times5}+\dfrac{1}{4\times5\times6}+\dfrac{1}{5\times6\times7}$
- $\dfrac{1}{n\times(n+1)\times(n+2)}=\dfrac{1}{2}\times\bigg\{\dfrac{1}{n\times(n+1)}-\dfrac{1}{(n+1)\times(n+2)}\bigg\}$を利用すると,
$\dfrac{1}{2}\bigg(\dfrac{1}{2}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{12}+\dfrac{1}{12}-\dfrac{1}{20}+\dfrac{1}{20}-\dfrac{1}{30}+\dfrac{1}{30}-\dfrac{1}{42}\bigg)$
$=\dfrac{1}{2}\bigg(\dfrac{1}{2}-\dfrac{1}{42}\bigg)$
$=$$\dfrac{5}{21}$
- $\dfrac{1}{n\times(n+1)\times(n+2)}=\dfrac{1}{2}\times\bigg\{\dfrac{1}{n\times(n+1)}-\dfrac{1}{(n+1)\times(n+2)}\bigg\}$を利用すると,