問題
次の式を2重根号を外して簡単にせよ.
解説
- (1) $\sqrt{4+\sqrt{7}}$
- $=\sqrt{\bigg(\sqrt{\dfrac{7}{2}}+\sqrt{\dfrac{1}{2}}\bigg)^{2}}
=\sqrt{\dfrac{7}{2}}+\sqrt{\dfrac{1}{2}}$
$=$$\dfrac{\sqrt{14}+\sqrt{2}}{2}$
- $=\sqrt{\bigg(\sqrt{\dfrac{7}{2}}+\sqrt{\dfrac{1}{2}}\bigg)^{2}}
- (2) $\sqrt{7-\sqrt{33}}$
- $=\sqrt{\bigg(\sqrt{\dfrac{11}{2}}-\sqrt{\dfrac{3}{2}}\bigg)^{2}}
=\sqrt{\dfrac{11}{2}}-\sqrt{\dfrac{3}{2}}$
$=$$\dfrac{\sqrt{22}-\sqrt{6}}{2}$
- $=\sqrt{\bigg(\sqrt{\dfrac{11}{2}}-\sqrt{\dfrac{3}{2}}\bigg)^{2}}
- (3) $\sqrt{10+5\sqrt{3}}$
- $=\sqrt{\bigg(\sqrt{\dfrac{15}{2}}+\sqrt{\dfrac{5}{2}}\bigg)^{2}}
=\sqrt{\dfrac{15}{2}}+\sqrt{\dfrac{5}{2}}$
$=$$\dfrac{\sqrt{30}+\sqrt{10}}{2}$
- $=\sqrt{\bigg(\sqrt{\dfrac{15}{2}}+\sqrt{\dfrac{5}{2}}\bigg)^{2}}
